If your intention is to count the number of (col1, col2) (-- both col as a single integral unit) Then maybe use group by is better. eg: select col1, col2, count(*) from demo group by col1, col2; Or …

Apr 23, 2015 · Try something like this: SELECT el.emali_list_name AS EmailList ,COUNT(*) AS EmailsCount ,SUM(CASE WHEN ed.blacklist = 1 THEN 1 ELSE 0 END) AS …

count(*), you can think it as count everything, including NULLs count(*) over() will count how many rows in your result set, in your case, because you did GROUP BY on [ID] column, which I …

May 11, 2020 · You can use the APPLY operator to count the number of employees active at the termination date. As I looked at the question at first I missed that there were different …

using the case you can define any range you want.. select case when RESULT between 0 and 50 then '0-50' when RESULT between 50 and 100 then '51-100' when RESULT between 100 and …

Sep 14, 2015 · Here is the catch: the mid count is a separate row instead of a column; Here is the query. SELECT mid,IFNULL(pid,0) pid,knt count FROM ( SELECT mid,pid,COUNT(id) knt …

Nov 15, 2022 · Without a GROUP BY, COUNT (or SUM, etc) scans the entire table and delivers and summarizes the tally in a single row. Since there will be only one row in your query, which …

Oct 28, 2016 · Convert the null values to some other text (blank or '[NULL]') and count those. You can Use either if null or coalesce to change the null value.

Aug 2, 2017 · If your professor is talking about SQL, the statement is wrong. COUNT(x) will return the number of rows where x IS NOT NULL including duplicates. COUNT(*) or …

Aug 13, 2015 · ERROR 1140 (42000): Mixing of GROUP columns (MIN(),MAX(),COUNT(),...) with no GROUP columns is illegal if there is no GROUP BY clause However, a slight modification …