The way Python indexing works is that it starts at 0, so the first number of your list would be [0].You would have to print[52], as the starting index is 0 and therefore line 53 is [52].

this makes the size of the list just big enough to hold 2 elements, the two you added, which has an index of 0 and 1 (python lists are 0-based). In your code, further down, you then specify the contents of element j which starts at 2, and your code blows up immediately because you're trying to say "for a list of 2 elements, please store the ...

This style was common before python introduced conditional expressions (v = a if condition else b), but has been out of style for many years. – Ryan Haining Commented Oct 22, 2021 at 16:37

Generally it means that you are providing an index for which a list element does not exist. E.g, if your list was [1, 3, 5, 7] , and you asked for the element at index 10, you would be well out of bounds and receive an error, as only elements 0 through 3 exist.

Feb 13, 2012 · Here is your code. I'm assuming you're using python 3 based on the your use of print() and input():. import random def main(): #random.seed() --> don't need random.seed() #Prompts the user to enter the number of tickets they wish to play.

Jul 24, 2016 · By starting at the end of the list and moving backwards, you avoid the problem of running off the end of the list because you've shortened it. E.g. if you start with 'aabc' and move forwards, you'll use the indexes 0, 1, 2, and 3.

It means that you are trying to access an index of the list that do not exist. For example, the list ['a','b','c'] have 3 indices: 0, 1 and 2. list[0] = 'a'; list[1] = 'b'; list[2] = 'c' If you try list[3] then you will get 'IndexError: list index out of range'

En Python, las listas empiezan por 0. En tu caso, en la primera iteración del primer for, A[j] vale 9. C sólo tiene 9 elementos, por lo que sólo podrías acceder hasta C[8] .

Jul 16, 2012 · I'm attempting to get Python to populate the lists with the closing prices of 500 stocks. While the code seems to work fine for just a few stocks, the large amount poses a problem. Python keeps giving me the following error: "OneClose.append(Data[i][4]) IndexError: list index out of range." I'm not sure how to remedy this problem.

Apr 11, 2018 · Is there clean way to get the value at a list index or None if the index is out or range in Python? The obvious way to do it would be this: if len(the_list) > i: return the_list[i] else: return None However, the verbosity reduces code readability. Is there a clean, simple, one-liner that can be used instead?